NCERT SOLUTIONS

NCERT SOLUTIONS

1. Sets
2. Relations and Functions
3. Trigonometric Functions
4. Principle of Mathematical Induction
5. Complex Numbers and Quadratic Equations
6. Linear Inequalities
7. Permutations and Combinations
8. Binomial Theorem
9. Sequences and Series
10. Straight Lines
11. Conic Sections
12. Introduction to Three Dimensional Geometry
13. Limits and Derivatives
14. Mathematical Reasoning
15. Statistics
16. Probability

NCERT SOLUTIONS

Chapter 2. Units and Measurements

Chapter 3. Motion in a Straight Line

Chapter 4. Motion in a Plane

Chapter 5. Laws of Motion

Chapter 6. Work, Energy and Power

Chapter 7. System of Particles and Rotational Motion

Chapter 8. Gravitation

Chapter 9. Mechanical Properties Of Solids

Chapter 10. Mechanical Properties Of Fluids

Chapter 11. Thermal Properties Of Matter

Chapter 12. Thermodynamics

Chapter 13. Kinetic Theory

Chapter 14. Oscillations

Chapter 15. Waves

NCERT SOLUTIONS

1. Some Basic Concepts of Chemistry
2. Structure of Atom
3. Classification of Elements and Periodicity in Properties
4. Chemical Bonding and Molecular Structure
5. States of Matter
6. Thermodynamics
7. Equilibrium
8. Redox Reactions
9. Hydrogen
10. The s-Block Elements
11. The p-Block Elements
12. Organic Chemistry – Some Basic Principles and Techniques
13. Hydrocarbons
14. Environmental Chemistry

PART I - INDIAN ECONOMY

1. Indian Economy on the Eve of Independence
2. Indian Economy:1950-1990
3. IE-3. Economic Reforms Since 1991
4. IE-4. Poverty
5. IE-5. Human Capital Formation in India
6. IE-6. Rural Development
7. IE-7. Employment : Growth, Information and Other Issues
8. IE-8. Infrastructure
9. IE-9. Environment and Sustainable Development
10. IE-10. Development Experiences of India : A Comparison with Neighbours

PART II - STATISTICS IN ECONOMICS

1. Introduction to Economics
2. Stat-2. Collection of Data
3. Stat-3. Organization of Data
4. Stat-4. Presentation of Data
5. Stat-5. Measures of Central Tendency
6. Stat-6. Measures of Dispersion
7. Stat-7. Correlation
8. Stat-8. Index Numbers
9. Stat-9. Use of Statistical Tools

NCERT SOLUTIONS

1. Relations and Functions
2. Inverse Trigonometric Functions
3. Matrices
4. Determinants
5. Continuity and Differentiability
6. Application of Derivatives
7. Integrals
8. Application of Integrals
9. Differential Equations
10. Vector Algebra
11. Three Dimensional Geometry
12. Linear Programming
13. Limits and Derivatives
14. Probability
15. Supplementary Material

NCERT SOLUTIONS

1. Electric Charges And Fields
2. Electrostatic Potential And Capacitance
3. Current Electricity
4. Moving Charges And Magnetism
5. Magnetism And Matter
6. Electromagnetic Induction
7. Electromagnetic Waves
8. Ray Optics And Optical Instruments
9. Wave Optics
10. Dual Nature Of Radiation And Matter
11. Atoms
12. Nuclei
13. Semiconductor Electronics: Materials, Devices And Simple Circuits
14. Communication Systems

NCERT SOLUTIONS

1. The Solid State
2. Solutions
3. Electrochemistry
4. Chemical Kinetics
5. Surface Chemistry
6. General Principles and Processes of Isolation of Elements
7. The p-Block Elements
8. The d-and f-Block Elements
9. Coordination Compounds

1. Haloalkanes and Haloarenes
2. Alcohols, Phenols and Ethers
3. Aldehydes, Ketones and Carboxylic Acids
4. Amines
5. Biomolecules
6. Polymers
7. Chemistry in Everyday Life

NCERT SOLUTIONS

Q: A spaceship is stationed on Mars. How much energy must be expended on the spaceship to launch it out of the solar system? Mass of the space ship = 1000 kg; mass of the Sun = 2 × 1030 kg; mass of mars = 6.4 × 1023 kg; radius of mars = 3395 km; radius of the orbit of mars = 2.28 × 108 kg; G= 6.67 × 10–11 N m2 kg–2.

More questions like this

Given,

Mass of the spaceship, m = 1000 kg

Mass of the Sun, MS = 2 × 1030 kg

Mass of Mars, MM = 6.4 × 1023 kg

Orbital radius of Mars, R = 2.28 × 108 km =2.28 × 1011 m

Radius of Mars, r = 3395 km = 3.395 × 106 m

Universal gravitational constant, G= 6.67 × 10–11 N m2 kg–2

Potential energy of the spaceship due to the gravitational attraction of the Sun

Potential energy of the spaceship due to the gravitational attraction of Mars

Since, the spaceship is stationed on Mars, its velocity and hence, its kinetic energy will be zero.

Therefore, total energy of the spaceship

Energy required for launching the spaceship out of the solar system

Q: An oil drop of 12 excess electrons is held stationary under a constant electric field of 2.55 × 104 N C−1 in Millikan’s oil drop experiment. The density of the oil is 1.26 g cm−3. Estimate the radius of the drop. (g = 9.81 m s−2; e = 1.60 × 10−19 C).

More questions like this

Since the drop is stationary, force (FE) due to electric field E is equal to the weight of the oil drop (W)

Let the radius of the oil drop be r

Mass of the oil drop m = Volume of the drop × Density of oil

Electrostatic Force FE = qE

Excess electrons on an oil drop, n = 12

Charge on an electron, e = 1.6 × 10−19 C

q = Net charge on the oil drop = n e

= 12 × 1.6 × 10−19 C

Electric field intensity, E = 2.55 × 104 N C−1

Density of oil, ρ = 1.26 gm/cm3 = 1.26×103 kg/m3

Acceleration due to gravity, g = 9.81 m s−2

Putting the values in

$r=\sqrt[3]{\frac{3Ene}{4\pi \rho g}}$

$=\sqrt[3]{\frac{3×2.55×{10}^{4}×12×1.6×{10}^{-19}}{4×3.14×1.26×{10}^{3}×9.81}}$