CBSE NOTES CLASS 11 PHYSICS CHAPTER 6
WORK, ENERGY & POWER
Work is done by a force on the body over a certain displacement.
The work done by the force is defined to be the product of component of the force in the direction of the displacement and the magnitude of this displacement. Thus
If we take the vectors and
W = . = F s cos θ, where θ is the angle between and .
No work is done if,
- the displacement is zero
- the force is zero.
- the force and displacement are mutually perpendicular.
For the block moving on a smooth horizontal table, the gravitational force m g does no work since it acts at right angles to the displacement.
Assuming the moon’s orbits around the earth is perfectly circular then the earth’s gravitational force does not do any work.
Work can be both positive and negative. If θ is between 0o and 90o, cos θ is positive. If θ is between 90o and 180o, cos θ is negative.
The frictional force opposes displacement and θ = 180o, hence the work done by friction is negative (cos 180o = –1).
Energy of a body by virtue of its motion is called kinetic energy.
K = mv2
The Work Energy (WE) Theorem
The change in kinetic energy of a particle is equal to the work done on it by the net force.
Work and energy have the same dimensions, [ML2T–2].
The SI unit of both work and energy is Joule (J).
As per third equation of rectilinear motion,
v2 − u2 = 2 a s
where u and v are the initial and final speeds and s the distance traversed.
Multiplying both sides by m/2, we have
mv2 – m u2 = m a s
⇒ mv2 – mu2 = F s
Where the last step is from Newton’s Second Law, i.e., F = m a.
Kf − Ki = W
where Ki and Kf are the initial and final kinetic energies of the object, respectively.
Work Done By a Variable Force
Consider a plot of x and F(x).
We can divide the area into area elements of equal widths, Δx.
If the displacement Δx is small, we can take the force F(x) as approximately constant and the work done is then
ΔW = F(x) Δx
Adding successive rectangular areas, we get the total work done as
If we take limit as displacements approach zero, then the sum approaches a definite value equal to the area under the curve or the integral,
Work Energy Theorem for a Variable Force
The time rate of change of kinetic energy is
Or dK = F(x) dx
Integrating from the initial position (xi ) to final position ( xf ), we have
⇒ Kf − Ki = W
Potential energy is the stored energy of an object. It is the energy by virtue of an object's position or configuration relative to other objects.
Potential energy is associated with restoring force.
Examples of potential energy are gravitational potential energy, electric potential energy energy stored in a stretched spring, etc.
Mathematically, the potential energy V(x) is defined if the force F(x) can be written as
The change in potential energy, for a conservative force, ΔV is equal to the negative of the work done by the force
ΔV = − F(x) Δx
Gravitational potential energy
V(h) = mgh,
where h is the height of the object from the surface of the earth.
- A force F(x) is conservative if it can be derived from a scalar quantity V(x) by the relation given by ΔV = − F(x) Δx.
- The work done by the conservative force depends only on the end points and not on the path followed.
W = Kf – Ki = V (xi ) – V(xf )
- The work done by conservative force in a closed path is zero.
- We can find difference of Potential Energies between two points, but cannot find absolute Potential Energies.
- Time is not considered in the discussion.
Conservation of Total Mechanical Energy
The total mechanical energy of a system is conserved if the forces, doing work on it, are conservative.
K + V = constant = Total mechanical energy
ΔK + ΔV = 0
Example – Consider a ball is dropped from height h.
TE at the top when the ball is at rest is PE = mgh
When the ball reaches the ground the PE becomes 0 and all the PE is converted to KE.
Just before hitting the ground,
Or v =
Example – Vertical circle
The potential energy of the system is taken to be zero at the lowest point A.
Tc = 0
Comparing with the equation at A, we have
At point B,
The Potential Energy of a Stretched Spring
The spring force is conservative. The system consists of a block attached to a spring and resting on a smooth horizontal surface. The other end of the spring is attached to a rigid wall.
- The spring is considered to be massless.
- The surface has been considered to possess negligible friction.
Spring force is given by Hooke’s law
Fs = − k x
The constant k is called the spring constant. Its unit is N m-1. The spring is said to be stiff if k is large and soft if k is small.
If the block is pulled outwards and the maximum extension is xm, the work done by the spring (restoring) force is
The work done by the external pulling force F is positive.
The same is true when the spring is compressed with a displacement xc (< 0).
If the block is moved from an initial displacement xi to a final displacement xf , the work done by the spring force Ws is
Thus the work done by the spring force depends only on the end points. Specifically, if the block is pulled from xi and allowed to return to xi; Ws = 0.
⇒ Hence, the spring force is a conservative force.
- The potential energy V(x) of the spring to be zero when block and spring system is in the equilibrium position. For an extension (or compression) x,
- Total energy of the block,
When x = 0, v = vm
Plots of the Potential Energy and Kinetic Energy of a Spring
Plots of the potential energy V and kinetic energy K of a block attached to a spring obeying Hooke’s law, are parabolic. The two plots are complementary, one decreasing as the other increases. The total mechanical energy E = K + V remains constant.
Work Done by Combination of Conservtive and Non-conservative Forces
If the two forces on the body consist of a conservative force Fc and a non-conservative force Fnc, the conservation of mechanical energy formula will be,
(Fc+ Fnc ) Δx = ΔK
But Fc Δx = − ΔV
Hence, Δ(K + V) = Fnc Δx
ΔE = Fnc Δx
Ef − Ei = Wnc
Where, Wnc is the total work done by the non-conservative forces over the path.
- Take up example 9
Various forms of energy
Energy exists in various forms which can transform into one another.
- Mechanical Energy – KE and PE
- Heat Energy
- Electrical Energy
- Light Energy
- Chemical Energy
- Nuclear Energy
Conservation of Total Energy
The total energy of the universe is constant. If one part of the universe loses energy, another part must gain an equal amount of energy.
The principle of conservation of energy cannot be proved. However, no violation of this principle has been observed.
Power is defined as the time rate at which work is done or energy is transferred.
The average power of a force is defined as the ratio of the work, W, to the total time t taken
Work dW done by a force F for a displacement dr is, . The instantaneous power can therefore be expressed as
Power is a scalar quantity. Its dimensions are [ML2T–3].
The SI unit is called a watt (W).
- 1 watt = 1 Js–1.
- 1 Horse-power (hp) = 746 W
- 1 kilowatt hour (kWh) of energy
= 1000 (watt).1 (hour) = 1000 watt hour
=1 kilowatt hour (kWh)
= 103 (W) × 3600 (s)
= 3.6 × 106 J
- Electrical energy is measured in units of kWh.
Consider two masses m1 and m2. The particle m1 is moving with speed u1 and m2 is at rest.
The mass m1 collides with the stationary mass m2 and m1 and m2 move with velocities v1 and v2 respectively, after the collision. v1 and v2 make angle θ1 and θ2 respectively with the original direction of u1.
In all collisions the total linear momentum is conserved, that is, the initial momentum of the system is equal to the final momentum of the system.
Δp1 = F12 Δt
Δp2 = F21 Δt
where F12 is the force exerted on the first particle by the second particle and F21 is the force exerted on the second particle by the first particle.
Now from Newton’s Third Law, F12 = − F21. This implies
Δp1 + Δp2 = 0
The total kinetic energy of the system is not necessarily conserved. The impact and deformation during collision may generate heat and sound. Part of the initial kinetic energy is transformed into other forms of energy.
Collisions in one dimension
θ1 = θ2 = 0
If the kinetic energy is not conserved, the collision is called inelastic collision. That is the KE before and after collision is not the same.
Completely Inelastic Collision
A collision in which the two particles move together after the collision is called a completely inelastic collision.
By conservation of momentum,
m1u1 = (m1 + m2)v [v is same for both]
The loss in kinetic energy on collision is
Putting the value of v,
If the kinetic energy is conserved, the collision is called elastic collision. That is the KE before and after collision is same.
By conservation of momentum,
m1u1 = m1v1 + m2v2
⇒ m1 (u1 - v1) = m2v2 -(1)
By conservation of kinetic energy,
Dividing relation (2) by (1)
u1 + v1 = v2
Putting the value of v2 in (1)
If the two masses are equal v1= 0
v2 = u1
The first mass comes to rest and pushes off the second mass with its initial speed on collision.
Case II: If one mass dominates, e.g. m2 > > m1
v1 ~ − u1 and v2 ~ 0
The heavier mass is undisturbed while the lighter mass reverses its velocity.
Coefficient of restitution e
The coefficient is related to energy by
Range of values for e
e is usually a positive, real number between 0 and 1.
e = 0: This is a perfectly inelastic collision. The objects do not move apart after the collision, but instead they coalesce. Kinetic energy is converted to heat or work done in deforming the objects.
0 < e < 1: This is a real-world inelastic collision, in which some kinetic energy is dissipated.
e = 1: This is a perfectly elastic collision, in which no kinetic energy is dissipated, and the objects rebound from one another with the same relative speed with which they approached.
e < 0: A collision in which the separation velocity of the objects has the same direction (sign) as the closing velocity, implying the objects passed through one another without fully engaging. This may also be thought of as an incomplete transfer of momentum. An example of this might be a small, dense object passing through a large, less dense one – e.g., a bullet passing through a target, or a motorcycle passing through a motor home or a wave tearing through a dam.
Collisions in Two Dimensions
Conserving the momentum in x - direction,
m1u1 = m1v1 cos θ1 + m2v2 cos θ2
Conserving the momentum in y - direction,
0 = m1v1 sin θ1 − m2v2 sin θ2
If the collision is elastic then,
Now we have four unknowns (v1, v2, θ1, θ2) but only 3 equations. If one of the variables is known, we can solve for other 3 variables.